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KPSKV Khalwa Nautan Siwan

Study Material › CBSE › Class 6 › Mathematics › Notes

Revision Notes on Constructions

Learning Goal

1. The perpendicular bisector of a line segment (using ruler and compass)

2. Perpendicular to a line from a point not on it (using ruler and a compass)

3. The bisector of an angle

Perpendiculars

If two lines intersect in such a way that they make a right angle at the point of intersection then they are perpendicular to each other.

Perpendiculars

 

1. The perpendicular bisector of a line segment (using ruler and compass)

Step 1: Draw a line segment AB.

Line segment AB

Step 2: Take A as the centre and draw two arcs – one upside and one downside with the radius of more than half of the length of AB. Or you can draw a circle taking A as the centre for the convenience.

Again make the arcs with taking B as the centre so that they intersect the previous arcs.

Two arcs – one upside and one downside

Step 3: Join the intersections of the arcs and name them as C and D.

Join the intersections of the arcs

Step 4: The required perpendicular bisector of AB is CD. Hence, AO = OB.

2. Perpendicular to a line from a point not on it (using ruler and a compass)

Step 1: P is the point outside the given line l.

Step 2: Take P as the centre and draw a big arc of any radius which intersects line l at two points A and B.

Two points A and B.

Step 3: Take A and B as radius and draw arcs from both points with the same radius as taken before so that they intersect with each other.

intersect with each other.

Step 4: Join PQ.

PQ is the perpendicular to line l.

PQ is the perpendicular to line l.

3. The bisector of an angle

An angle bisector is the line segment which divides a particular angle into two equal parts. It is also called the line of symmetry of the angle.

Construction of angle bisector (using a ruler and a compass)

Draw the angle bisector of ∠O.

Angle bisector of ∠O

Step 1: Put the pointer on O and draw an arc of any radius so that it cut the rays at point A and B.

cut the rays at point A and B.

Step 2: Put the pointer on point A and draw an arc of the radius of more than half of AB.

Arc of the radius of more than half of AB.

Step 3: While taking B as the centre we will draw an arc of the same radius so that it cut the previous arc at point C.

Arc at point C

Step 4: Join OC.OC is the required angle bisector of ∠O.

The required angle bisector of ∠O

Hence, ∠BOC = ∠COA.